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Exponential Function Solution Equation - Decay (Continuous, Mis-matched Time Units) Equation to Starting Value

Level 1

The topics in this unit focus on mastering exponential growth and decay functions. Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

WorksheetView

Exponential Function Solution Equation - Decay (Continuous, Mis-matched Time Units) Equation to Starting Value Worksheet

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Exponential Function Solution Equation - Decay (Continuous, Mis-match...
1
Rearrange this equation to solve for the starting concentration given this model of a continuous decay of a radioactive material?
A LaTex expression showing 245 =R sub 0 times e to the power of (-0.04 times 5 over 7 )
a A LaTex expression showing R sub 0 = e to the power of (-0.04 times \frac{5 over 7 ) }{245}
b A LaTex expression showing R sub 0 = 245 over e to the power of (\frac{-0.04 {5 times 7 )}}
c A LaTex expression showing R sub 0 = 245 over e to the power of (-0.04 times \frac{5 {7 )}}
2
Rearrange this equation to solve for the starting concentration given this model of a continuous decay of a radioactive material?
A LaTex expression showing 266 =R sub 0 times e to the power of (-0.06 times 2 over 7 )
a A LaTex expression showing R sub 0 = 266 over e to the power of (-0.06 times \frac{2 {7 )}}
b A LaTex expression showing R sub 0 = 266 over e to the power of (\frac{-0.06 {2 times 7 )}}
c A LaTex expression showing R sub 0 = e to the power of (-0.06 times \frac{2 over 7 ) }{266}
3
Rearrange this equation to solve for the starting population given this model of a a continuously declining bacteria population?
A LaTex expression showing 688 =P sub 0 times e to the power of (-0.05 times 3 over 365 )
a A LaTex expression showing P sub 0 = e to the power of (-0.05 times \frac{3 over 365 ) }{688}
b A LaTex expression showing P sub 0 = 688 over e to the power of (-0.05 times \frac{3 {365 )}}
c A LaTex expression showing P sub 0 = 688 over e to the power of (\frac{-0.05 {3 times 365 )}}
4
Rearrange this equation to solve for the starting population given this model of a continuous decline of a whale population?
A LaTex expression showing 610 =P sub 0 times e to the power of (-0.09 times 3 times 4)
a A LaTex expression showing P sub 0 = \frac{e to the power of (-0.09 times 3 times 4) }{610}
b A LaTex expression showing P sub 0 = 610 over e to the power of (\frac{-0.09 {3 over 4 )}}
c A LaTex expression showing P sub 0 = 610 over e to the power of (-0.09 times 3 times 4)
5
Rearrange this equation to solve for the starting concentration given this model of a continuous decay of a radioactive material?
A LaTex expression showing 510 =R sub 0 times e to the power of (-0.09 times 5 times 7)
a A LaTex expression showing R sub 0 = 510 over e to the power of (-0.09 times 5 times 7)
b A LaTex expression showing R sub 0 = 510 over e to the power of (\frac{-0.09 {5 over 7 )}}
6
Rearrange this equation to solve for the starting population given this model of a a continuously declining bacteria population?
A LaTex expression showing 550 =P sub 0 times e to the power of (-0.06 times 4 over 7 )
a A LaTex expression showing P sub 0 = e to the power of (-0.06 times \frac{4 over 7 ) }{550}
b A LaTex expression showing P sub 0 = 550 over e to the power of (\frac{-0.06 {4 times 7 )}}
c A LaTex expression showing P sub 0 = 550 over e to the power of (-0.06 times \frac{4 {7 )}}
7
Rearrange this equation to solve for the starting population given this model of a continuous decline of a bird population?
A LaTex expression showing 134 =P sub 0 times e to the power of (-0.05 times 8 over 4 )
a A LaTex expression showing P sub 0 = e to the power of (-0.05 times \frac{8 over 4 ) }{134}
b A LaTex expression showing P sub 0 = 134 over e to the power of (-0.05 times \frac{8 {4 )}}
c A LaTex expression showing P sub 0 = 134 over e to the power of (\frac{-0.05 {8 times 4 )}}
8
Rearrange this equation to solve for the starting population given this model of a a continuously declining bacteria population?
A LaTex expression showing 666 =P sub 0 times e to the power of (-0.05 times 6 times 12)
a A LaTex expression showing P sub 0 = 666 over e to the power of (-0.05 times 6 times 12)
b A LaTex expression showing P sub 0 = 666 over e to the power of (\frac{-0.05 {6 over 12 )}}