Exponential Function Solution Equation - Decay (Continuous) - Scenario to Time

Level 1

This math topic focuses on applying and rearranging exponential decay equations to solve for time. The scenarios provided involve continuous decay rates of various percentages affecting different populations or substances (bacteria, whale populations, radioactive isotopes, toxins, etc.). Each problem requires students to manipulate exponential decay formulas to find out how long it takes for these populations or concentrations to reduce to a specific number, teaching them practical applications of logarithmic and exponential functions in real-life situations like biology and environmental science.

Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

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Exponential Function Solution Equation - Decay (Continuous) - Scenario to Time Worksheet

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Exponential Function Solution Equation - Decay (Continuous) - Scenari...
1
A bacteria population starts at 600. It declines continuously at 5% per month. After a certain number of months it has decreased to a population of 516 bacteria.
Rearrange the exponential equation to solve for for the time given this scenario?
a A LaTex expression showing t = -0.05 over \ln{\frac{516 {600}}}
b A LaTex expression showing t = +\frac{\ln{516 times 600}}{0.05}
c A LaTex expression showing t = -\ln{\frac{516 over 600 }}{0.05}
2
A whale population starts at 200. It declines continuously at 4% per quarter. After a certain number of quarters it has decreased to a population of 145 whales.
Rearrange the exponential equation to solve for for the time given this scenario?
a A LaTex expression showing t = +\frac{\ln{145 times 200}}{0.04}
b A LaTex expression showing t = -0.04 over \ln{\frac{145 {200}}}
c A LaTex expression showing t = -\ln{\frac{145 over 200 }}{0.04}
3
A radioactive material starts at an isotope concentration of 300ppm. It decays continuously at 6% per day. After a certain number of days it has decayed to an isotope concentration of 222ppm.
Rearrange the exponential equation to solve for for the time given this scenario?
a A LaTex expression showing t = -\ln{\frac{222 over 300 }}{0.06}
b A LaTex expression showing t = +\frac{\ln{222 times 300}}{0.06}
4
A bacteria population starts at 500. It declines continuously at 2% per month. After a certain number of months it has decreased to a population of 417 bacteria.
Rearrange the exponential equation to solve for for the time given this scenario?
a A LaTex expression showing t = -0.02 over \ln{\frac{417 {500}}}
b A LaTex expression showing t = -\ln{\frac{417 over 500 }}{0.02}
c A LaTex expression showing t = +\frac{\ln{417 times 500}}{0.02}
5
A radioactive material starts at an isotope concentration of 500ppm. It decays continuously at 2% per hour. After a certain number of hours it has decayed to an isotope concentration of 470ppm.
Rearrange the exponential equation to solve for for the time given this scenario?
a A LaTex expression showing t = +\frac{\ln{470 times 500}}{0.02}
b A LaTex expression showing t = -\ln{\frac{470 over 500 }}{0.02}
6
A bird population starts at 500. It declines continuously at 7% per year. After a certain number of years it has decreased to a population of 285.
Rearrange the exponential equation to solve for for the time given this scenario?
a A LaTex expression showing t = +\frac{\ln{285 times 500}}{0.07}
b A LaTex expression showing t = -0.07 over \ln{\frac{285 {500}}}
c A LaTex expression showing t = -\ln{\frac{285 over 500 }}{0.07}
7
A toxin starts at a concentration of 600mg/L. It declines continuously at 2% per month. After a certain number of months it has decreased to a concentration of 521mg/L.
Rearrange the exponential equation to solve for for the time given this scenario?
a A LaTex expression showing t = -0.02 over \ln{\frac{521 {600}}}
b A LaTex expression showing t = -\ln{\frac{521 over 600 }}{0.02}
c A LaTex expression showing t = +\frac{\ln{521 times 600}}{0.02}
8
A bird population starts at 700. It declines continuously at 3% per quarter. After a certain number of quarters it has decreased to a population of 620.
Rearrange the exponential equation to solve for for the time given this scenario?
a A LaTex expression showing t = +\frac{\ln{620 times 700}}{0.03}
b A LaTex expression showing t = -\ln{\frac{620 over 700 }}{0.03}
c A LaTex expression showing t = -0.03 over \ln{\frac{620 {700}}}