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Exponential Function Solution Equation - Decay (Discrete, Mis-matched Time Units) Equation to Starting Value

Level 1

The topics in this unit focus on mastering exponential growth and decay functions. Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

WorksheetView

Exponential Function Solution Equation - Decay (Discrete, Mis-matched Time Units) Equation to Starting Value Worksheet

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Exponential Function Solution Equation - Decay (Discrete, Mis-matched...
1
Rearrange this equation to solve for the starting concentration given this model of a decline of a toxin concentration (hourly dialysis)?
A LaTex expression showing 258 =C sub 0 times (1-0.09) to the power of (7 times 24)
a A LaTex expression showing C sub 0 = 258 over (1+0.09) to the power of 7 times 24
b A LaTex expression showing C sub 0 = 258 over (1-0.09) to the power of 7 times 24
2
Rearrange this equation to solve for the starting concentration given this model of a decline of a toxin concentration (daily dialysis)?
A LaTex expression showing 124 =C sub 0 times (1-0.09) to the power of (5 times 7)
a A LaTex expression showing C sub 0 = 124 over (1+0.09) to the power of 5 times 7
b A LaTex expression showing C sub 0 = 124 times (1-0.09) to the power of 5 over 7
c A LaTex expression showing C sub 0 = 124 over (1-0.09) to the power of 5 times 7
3
Rearrange this equation to solve for the starting concentration given this model of a decline of a toxin concentration (daily dialysis)?
A LaTex expression showing 0 =C sub 0 times (1-0.09) to the power of (192 over 24 )
a A LaTex expression showing C sub 0 = 0 over (1-0.09) to the power of \frac{192 {24 }}
b A LaTex expression showing C sub 0 = 0 over (1+0.09) to the power of \frac{192 {24 }}
c A LaTex expression showing C sub 0 = 0 times (1-0.09) to the power of 192 times 24
4
Rearrange this equation to solve for the starting cash given this model of a balance of a charitable endowment (daily disbursements)?
A LaTex expression showing 795 =P sub 0 times (1-0.06) to the power of (2 times 365)
a A LaTex expression showing P sub 0 = 795 over (1+0.06) to the power of 2 times 365
b A LaTex expression showing P sub 0 = 795 times (1-0.06) to the power of 2 over 365
c A LaTex expression showing P sub 0 = 795 over (1-0.06) to the power of 2 times 365
5
Rearrange this equation to solve for the starting concentration given this model of a decline of a toxin concentration (daily dialysis)?
A LaTex expression showing 441 =C sub 0 times (1-0.05) to the power of (9 times 7)
a A LaTex expression showing C sub 0 = 441 times (1-0.05) to the power of 9 over 7
b A LaTex expression showing C sub 0 = 441 over (1-0.05) to the power of 9 times 7
c A LaTex expression showing C sub 0 = 441 over (1+0.05) to the power of 9 times 7
6
Rearrange this equation to solve for the starting concentration given this model of a decline of a toxin concentration (weekly dialysis)?
A LaTex expression showing 29 =C sub 0 times (1-0.09) to the power of (35 over 7 )
a A LaTex expression showing C sub 0 = 29 over (1-0.09) to the power of \frac{35 {7 }}
b A LaTex expression showing C sub 0 = 29 times (1-0.09) to the power of 35 times 7
c A LaTex expression showing C sub 0 = 29 over (1+0.09) to the power of \frac{35 {7 }}
7
Rearrange this equation to solve for the starting concentration given this model of a decline of a toxin concentration (hourly dialysis)?
A LaTex expression showing 131 =C sub 0 times (1-0.08) to the power of (5 times 24)
a A LaTex expression showing C sub 0 = 131 over (1+0.08) to the power of 5 times 24
b A LaTex expression showing C sub 0 = 131 over (1-0.08) to the power of 5 times 24
8
Rearrange this equation to solve for the starting cash given this model of a balance of a charitable endowment (yearly disbursements)?
A LaTex expression showing 14 =P sub 0 times (1-0.03) to the power of (108 over 12 )
a A LaTex expression showing P sub 0 = 14 over (1-0.03) to the power of \frac{108 {12 }}
b A LaTex expression showing P sub 0 = 14 times (1-0.03) to the power of 108 times 12
c A LaTex expression showing P sub 0 = 14 over (1+0.03) to the power of \frac{108 {12 }}