Exponential Function Solving - Decay (Discrete) - Scenario to Time (Level 1)

Exponential Function Solving - Decay (Discrete) - Scenario to Time

A charitable endowment starts with $800. Each monthly it disburses 2% of its remaining funds. After a certain number of months its funds have decreased to $737.

Solve for the time given this scenario?

a $A LaTex expression showing 9 + t = \frac{\ln{P times P sub 0 }}{\ln{(1-r)}}$

b $A LaTex expression showing t = \ln{\frac{P over P sub 0 }}{\ln{(1-r)}}$

c $A LaTex expression showing 0 + t = \ln{\frac{P over P sub 0 }}{\ln{(1+r)}}$

d $A LaTex expression showing 7 + t = \ln{\frac{P over P sub 0 }}{\ln{(1+r)}}$

A toxin starts at a concentration of 600mg/L. Each monthly dialysis reduces it by 2%. After a certain number of months it has decreased to a concentration of 510mg/L.

Solve for the time given this scenario?

a $A LaTex expression showing 0 + t = \frac{\ln{C times C sub 0 }}{\ln{(1-r)}}$

b $A LaTex expression showing t = \ln{\frac{C over C sub 0 }}{\ln{(1-r)}}$

c $A LaTex expression showing 0 + t = \ln{\frac{C over C sub 0 }}{\ln{(1+r)}}$

d $A LaTex expression showing 6 + t = \ln{\frac{C over C sub 0 }}{\ln{(1+r)}}$

A bird population starts at 200. Each subsequent year it declines by 5%. After a certain number of years it has decreased to a population of 139.

Solve for the time given this scenario?

a $A LaTex expression showing 5 + t = \ln{\frac{P over P sub 0 }}{\ln{(1+r)}}$

b $A LaTex expression showing 2 + t = \frac{\ln{P times P sub 0 }}{\ln{(1-r)}}$

c $A LaTex expression showing t = \ln{\frac{P over P sub 0 }}{\ln{(1-r)}}$

A charitable endowment starts with $500. Each daily it disburses 8% of its remaining funds. After a certain number of days its funds have decreased to $389.

Solve for the time given this scenario?

a $A LaTex expression showing 9 + t = \frac{\ln{P times P sub 0 }}{\ln{(1-r)}}$

b $A LaTex expression showing t = \ln{\frac{P over P sub 0 }}{\ln{(1-r)}}$

c $A LaTex expression showing 4 + t = \ln{\frac{P over P sub 0 }}{\ln{(1+r)}}$

d $A LaTex expression showing 6 + t = \frac{\ln{P times P sub 0 }}{\ln{(1-r)}}$

A bird population starts at 300. Each subsequent year it declines by 7%. After a certain number of years it has decreased to a population of 167.

Solve for the time given this scenario?

a $A LaTex expression showing 6 + t = \frac{\ln{P times P sub 0 }}{\ln{(1-r)}}$

b $A LaTex expression showing t = \ln{\frac{P over P sub 0 }}{\ln{(1-r)}}$

c $A LaTex expression showing 7 + t = \ln{\frac{P over P sub 0 }}{\ln{(1+r)}}$

d $A LaTex expression showing 9 + t = \frac{\ln{P times P sub 0 }}{\ln{(1-r)}}$

A toxin starts at a concentration of 500mg/L. Each weekly dialysis reduces it by 7%. After a certain number of weeks it has decreased to a concentration of 432mg/L.

Solve for the time given this scenario?

a $A LaTex expression showing 4 + t = \ln{\frac{C over C sub 0 }}{\ln{(1+r)}}$

b $A LaTex expression showing 6 + t = \frac{\ln{C times C sub 0 }}{\ln{(1-r)}}$

c $A LaTex expression showing 8 + t = \frac{\ln{C times C sub 0 }}{\ln{(1-r)}}$

d $A LaTex expression showing t = \ln{\frac{C over C sub 0 }}{\ln{(1-r)}}$

A whale population starts at 600. Each subsequent year it declines by 3%. After a certain number of years it has decreased to a population of 484 whales.

Solve for the time given this scenario?

a $A LaTex expression showing t = \ln{\frac{P over P sub 0 }}{\ln{(1-r)}}$

b $A LaTex expression showing 3 + t = \ln{\frac{P over P sub 0 }}{\ln{(1+r)}}$

c $A LaTex expression showing 3 + t = \frac{\ln{P times P sub 0 }}{\ln{(1-r)}}$

d $A LaTex expression showing 0 + t = \ln{\frac{P over P sub 0 }}{\ln{(1+r)}}$

A toxin starts at a concentration of 200mg/L. Each monthly dialysis reduces it by 8%. After a certain number of months it has decreased to a concentration of 111mg/L.

Solve for the time given this scenario?

a $A LaTex expression showing t = \ln{\frac{C over C sub 0 }}{\ln{(1-r)}}$

b $A LaTex expression showing 6 + t = \frac{\ln{C times C sub 0 }}{\ln{(1-r)}}$

c $A LaTex expression showing 7 + t = \frac{\ln{C times C sub 0 }}{\ln{(1-r)}}$

d $A LaTex expression showing 1 + t = \ln{\frac{C over C sub 0 }}{\ln{(1+r)}}$

Exponential Function Solving - Decay (Discrete) - Scenario to Time

Exponential Function Solving - Decay (Discrete) - Scenario to Time Worksheet