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Exponential Function Solution Equation - Growth (Continuous, Mis-matched Time Units) Equation to Starting Value

Level 1

The topics in this unit focus on mastering exponential growth and decay functions. Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

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Exponential Function Solution Equation - Growth (Continuous, Mis-matched Time Units) Equation to Starting Value Worksheet

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Exponential Function Solution Equation - Growth (Continuous, Mis-matc...
1
Rearrange this equation to solve for the starting views given this model of a continuous exponential growth of social media post views?
A LaTex expression showing 938 =V sub 0 times e to the power of (0.07 times 9 times 12)
a A LaTex expression showing V sub 0 = 938 over e to the power of (\frac{0.07 {9 over 12 )}}
b A LaTex expression showing V sub 0 = 938 over e to the power of (0.07 times 9 times 12)
c A LaTex expression showing V sub 0 = \frac{e to the power of (0.07 times 9 times 12) }{938}
2
Rearrange this equation to solve for the starting population given this model of a continuous growth of a rabbit population?
A LaTex expression showing 1,016 =P sub 0 times e to the power of (0.04 times 6 times 4)
a A LaTex expression showing P sub 0 = 1016 over e to the power of (\frac{0.04 {6 over 4 )}}
b A LaTex expression showing P sub 0 = \frac{e to the power of (0.04 times 6 times 4) }{1016}
c A LaTex expression showing P sub 0 = 1016 over e to the power of (0.04 times 6 times 4)
3
Rearrange this equation to solve for the starting price given this model of a continuously compounding growth of a share price?
A LaTex expression showing 697 =S sub 0 times e to the power of (0.03 times 5 over 4 )
a A LaTex expression showing S sub 0 = e to the power of (0.03 times \frac{5 over 4 ) }{697}
b A LaTex expression showing S sub 0 = 697 over e to the power of (\frac{0.03 {5 times 4 )}}
c A LaTex expression showing S sub 0 = 697 over e to the power of (0.03 times \frac{5 {4 )}}
4
Rearrange this equation to solve for the starting population given this model of a continuous growth of a rabbit population?
A LaTex expression showing 404 =P sub 0 times e to the power of (0.06 times 5 times 4)
a A LaTex expression showing P sub 0 = 404 over e to the power of (\frac{0.06 {5 over 4 )}}
b A LaTex expression showing P sub 0 = \frac{e to the power of (0.06 times 5 times 4) }{404}
c A LaTex expression showing P sub 0 = 404 over e to the power of (0.06 times 5 times 4)
5
Rearrange this equation to solve for the starting debt given this model of a growth of debt on a credit card with continuous compounding?
A LaTex expression showing 456 =D sub 0 times e to the power of (0.06 times 7 over 4 )
a A LaTex expression showing D sub 0 = 456 over e to the power of (\frac{0.06 {7 times 4 )}}
b A LaTex expression showing D sub 0 = 456 over e to the power of (0.06 times \frac{7 {4 )}}
c A LaTex expression showing D sub 0 = e to the power of (0.06 times \frac{7 over 4 ) }{456}
6
Rearrange this equation to solve for the starting downloads given this model of a continuously compounding growth of app downloads?
A LaTex expression showing 889 =A sub 0 times e to the power of (0.08 times 3 over 12 )
a A LaTex expression showing A sub 0 = 889 over e to the power of (0.08 times \frac{3 {12 )}}
b A LaTex expression showing A sub 0 = e to the power of (0.08 times \frac{3 over 12 ) }{889}
c A LaTex expression showing A sub 0 = 889 over e to the power of (\frac{0.08 {3 times 12 )}}
7
Rearrange this equation to solve for the starting population given this model of a continuous growth of an insect population?
A LaTex expression showing 563 =P sub 0 times e to the power of (0.03 times 4 over 365 )
a A LaTex expression showing P sub 0 = 563 over e to the power of (0.03 times \frac{4 {365 )}}
b A LaTex expression showing P sub 0 = 563 over e to the power of (\frac{0.03 {4 times 365 )}}
c A LaTex expression showing P sub 0 = e to the power of (0.03 times \frac{4 over 365 ) }{563}
8
Rearrange this equation to solve for the starting population given this model of a continuous growth of a rabbit population?
A LaTex expression showing 313 =P sub 0 times e to the power of (0.09 times 5 over 4 )
a A LaTex expression showing P sub 0 = 313 over e to the power of (\frac{0.09 {5 times 4 )}}
b A LaTex expression showing P sub 0 = e to the power of (0.09 times \frac{5 over 4 ) }{313}
c A LaTex expression showing P sub 0 = 313 over e to the power of (0.09 times \frac{5 {4 )}}