Home
Grade 1Grade 2Grade 3Grade 4Grade 5Grade 6Grade 7Grade 8Grade 9Grade 10Grade 11Grade 12Math Themes
Explorers (Grades 1-3)Explorers Elite (1-3)Navigators (Grades 4-6)Navigators Elite (4-6)Challengers (Grades 7-9)Challengers Elite (7-9)Scholars (Grades 10-12)Scholars Elite (10-12)Schedule an Evaluation
Mobius MethodFlexible ClassesCompanySupport
Pricing
Ctrl+k
Sign InJoin

Exponential Function Solving - Growth (Continuous, Mis-matched Time Units) Equation to Starting Value

Level 1

The topics in this unit focus on mastering exponential growth and decay functions. Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

WorksheetView

Exponential Function Solving - Growth (Continuous, Mis-matched Time Units) Equation to Starting Value Worksheet

Mobius Math Academy logo
Exponential Function Solving - Growth (Continuous, Mis-matched Time U...
1
Solve for the starting views given this model of a continuous exponential growth of social media post views?
A LaTex expression showing 269 =V sub 0 times e to the power of (0.06 times 5 times 12)
a A LaTex expression showing V sub 0 = \frac{e to the power of (r times t times 12) }{V}
b A LaTex expression showing V sub 0 = V over e to the power of (\frac{r {t over 12 )}}
c A LaTex expression showing V sub 0 = V over e to the power of (r times t times 12)
2
Solve for the starting population given this model of a continuous growth of an insect population?
A LaTex expression showing 1,079 =P sub 0 times e to the power of (0.05 times 6 over 7 )
a A LaTex expression showing P sub 0 = P over e to the power of (r times \frac{t {7 )}}
b A LaTex expression showing P sub 0 = e to the power of (r times \frac{t over 7 ) }{P}
3
Solve for the starting views given this model of a continuous exponential growth of social media post views?
A LaTex expression showing 1,135 =V sub 0 times e to the power of (0.07 times 5 times 12)
a A LaTex expression showing V sub 0 = V over e to the power of (\frac{r {t over 12 )}}
b A LaTex expression showing V sub 0 = \frac{e to the power of (r times t times 12) }{V}
c A LaTex expression showing V sub 0 = V over e to the power of (r times t times 12)
4
Solve for the starting price given this model of a continuously compounding growth of a share price?
A LaTex expression showing 859 =S sub 0 times e to the power of (0.04 times 9 times 3)
a A LaTex expression showing S sub 0 = S over e to the power of (\frac{r {t over 3 )}}
b A LaTex expression showing S sub 0 = S over e to the power of (r times t times 3)
c A LaTex expression showing S sub 0 = \frac{e to the power of (r times t times 3) }{S}
5
Solve for the starting price given this model of a continuously compounding growth of a share price?
A LaTex expression showing 1,277 =S sub 0 times e to the power of (0.07 times 5 times 12)
a A LaTex expression showing S sub 0 = \frac{e to the power of (r times t times 12) }{S}
b A LaTex expression showing S sub 0 = S over e to the power of (r times t times 12)
6
Solve for the starting downloads given this model of a continuously compounding growth of app downloads?
A LaTex expression showing 381 =A sub 0 times e to the power of (0.04 times 6 times 7)
a A LaTex expression showing A sub 0 = \frac{e to the power of (r times t times 7) }{A}
b A LaTex expression showing A sub 0 = A over e to the power of (\frac{r {t over 7 )}}
c A LaTex expression showing A sub 0 = A over e to the power of (r times t times 7)
7
Solve for the starting cash given this model of a continuously compounding growth of money in a savings account?
A LaTex expression showing 690 =P sub 0 times e to the power of (0.02 times 7 times 3)
a A LaTex expression showing P sub 0 = P over e to the power of (\frac{r {t over 3 )}}
b A LaTex expression showing P sub 0 = P over e to the power of (r times t times 3)
c A LaTex expression showing P sub 0 = \frac{e to the power of (r times t times 3) }{P}
8
Solve for the starting population given this model of a continuous growth of an insect population?
A LaTex expression showing 732 =P sub 0 times e to the power of (0.05 times 4 over 7 )
a A LaTex expression showing P sub 0 = P over e to the power of (r times \frac{t {7 )}}
b A LaTex expression showing P sub 0 = P over e to the power of (\frac{r {t times 7 )}}
c A LaTex expression showing P sub 0 = e to the power of (r times \frac{t over 7 ) }{P}