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Exponential Function Solving - Growth (Continuous, Mis-matched Time Units) Scenario to Value at Time

Level 1

The topics in this unit focus on mastering exponential growth and decay functions. Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

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Exponential Function Solving - Growth (Continuous, Mis-matched Time Units) Scenario to Value at Time Worksheet

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Exponential Function Solving - Growth (Continuous, Mis-matched Time U...
1
A social media post starts with 600 views. Its view count grows continually by 5% each year.After 7 months it has a larger number of views.
How would you solve for the final views given this scenario?
a A LaTex expression showing V = V sub 0 times e to the power of (r times t over 12 )
b A LaTex expression showing V = V sub 0 - e to the power of (r times t times 12)
c A LaTex expression showing V = V sub 0 times e to the power of (r over \frac{t {12 })}
2
A company's share price starts at $600. It grows continuously at 2% growth per month. After 9 years it has increased to a certain share price.
How would you solve for the final price given this scenario?
a A LaTex expression showing S = S sub 0 times e to the power of (r times t times 12)
b A LaTex expression showing S = S sub 0 - e to the power of (r times t over 12 )
c A LaTex expression showing S = S sub 0 times e to the power of (r over t times 12 )
3
An app starts with 200 downloads. Its download count grows continually by 9% each month.After 4 years it has a larger number of downloads.
How would you solve for the final downloads given this scenario?
a A LaTex expression showing A = A sub 0 times e to the power of (r times t times 12)
b A LaTex expression showing A = A sub 0 times e to the power of (r over t times 12 )
c A LaTex expression showing A = A sub 0 - e to the power of (r times t over 12 )
4
A rabbit population starts at 600. It grows continuously at 8% growth per year. After 9 quarters it has increased to a certain population.
How would you solve for the final population given this scenario?
a A LaTex expression showing P = P sub 0 times e to the power of (r times t over 4 )
b A LaTex expression showing P = P sub 0 times e to the power of (r over \frac{t {4 })}
c A LaTex expression showing P = P sub 0 - e to the power of (r times t times 4)
5
An app starts with 800 downloads. Its download count grows continually by 9% each year.After 5 days it has a larger number of downloads.
How would you solve for the final downloads given this scenario?
a A LaTex expression showing A = A sub 0 times e to the power of (r times t over 365 )
b A LaTex expression showing A = A sub 0 - e to the power of (r times t times 365)
c A LaTex expression showing A = A sub 0 times e to the power of (r over \frac{t {365 })}
6
A credit card starts with $800 of debt. It grows continuously at 5% interest per year. After 2 quarters the debt has grown to a certain amount.
How would you solve for the final debt given this scenario?
a A LaTex expression showing D = D sub 0 - e to the power of (r times t times 4)
b A LaTex expression showing D = D sub 0 times e to the power of (r times t over 4 )
c A LaTex expression showing D = D sub 0 times e to the power of (r over \frac{t {4 })}
7
A bacteria population starts at 600. It grows continuously at 4% growth per year. After 5 months it has increased to a certain population.
How would you solve for the final population given this scenario?
a A LaTex expression showing P = P sub 0 - e to the power of (r times t times 12)
b A LaTex expression showing P = P sub 0 times e to the power of (r times t over 12 )
8
A company's share price starts at $300. It grows continuously at 2% growth per quarter. After 8 months it has increased to a certain share price.
How would you solve for the final price given this scenario?
a A LaTex expression showing S = S sub 0 times e to the power of (r times t over 3 )
b A LaTex expression showing S = S sub 0 - e to the power of (r times t times 3)
c A LaTex expression showing S = S sub 0 times e to the power of (r over \frac{t {3 })}