Exponential Function Solution Equation - Growth (Discrete, Mis-matched Time Units) - Equation to Time

Level 1

The topics in this unit focus on mastering exponential growth and decay functions. Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

Exponential Function Solution Equation - Growth (Discrete, Mis-matched Time Units) - Equation to Time Worksheet

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Exponential Function Solution Equation - Growth (Discrete, Mis-matche...
1
Rearrange this equation to solve for the time given this model of a growth in credit card debt with quarterly interest?
A LaTex expression showing 885 =700 times (1+0.04) to the power of (t times 4)
a A LaTex expression showing t = 4 times \ln{\frac{885 over 700 }}{\ln{(1+0.04)}}
b A LaTex expression showing t = 1 over 4 times \frac{\ln{885 times 700}}{\ln{(1+0.04)}}
c A LaTex expression showing t = 1 over 4 times \ln{\frac{885 over 700 }}{\ln{(1+0.04)}}
2
Rearrange this equation to solve for the time given this model of a growth in credit card debt with quarterly interest?
A LaTex expression showing 317 =200 times (1+0.08) to the power of (t times 4)
a A LaTex expression showing t = 1 over 4 times \ln{\frac{317 over 200 }}{\ln{(1+0.08)}}
b A LaTex expression showing t = 4 times \ln{\frac{317 over 200 }}{\ln{(1-0.08)}}
c A LaTex expression showing t = 4 times \ln{\frac{317 over 200 }}{\ln{(1+0.08)}}
d A LaTex expression showing t = 1 over 4 times \frac{\ln{317 times 200}}{\ln{(1+0.08)}}
3
Rearrange this equation to solve for the time given this model of a growth in credit card debt with quarterly interest?
A LaTex expression showing 835 =300 times (1+0.05) to the power of (t over 3 )
a A LaTex expression showing t = 1 over 3 times \ln{\frac{835 over 300 }}{\ln{(1-0.05)}}
b A LaTex expression showing t = 3 times \frac{\ln{835 times 300}}{\ln{(1+0.05)}}
c A LaTex expression showing t = 3 times \ln{\frac{835 over 300 }}{\ln{(1+0.05)}}
4
Rearrange this equation to solve for the time given this model of a quarterly compounding growth of money in a savings account?
A LaTex expression showing 530 =500 times (1+0.03) to the power of (t times 4)
a A LaTex expression showing t = 4 times \ln{\frac{530 over 500 }}{\ln{(1+0.03)}}
b A LaTex expression showing t = 1 over 4 times \frac{\ln{530 times 500}}{\ln{(1+0.03)}}
c A LaTex expression showing t = 4 times \ln{\frac{530 over 500 }}{\ln{(1-0.03)}}
d A LaTex expression showing t = 1 over 4 times \ln{\frac{530 over 500 }}{\ln{(1+0.03)}}
5
Rearrange this equation to solve for the time given this model of a yearly compounding growth of money in a savings account?
A LaTex expression showing 1,905 =400 times (1+0.05) to the power of (t over 4 )
a A LaTex expression showing t = 4 times \ln{\frac{1905 over 400 }}{\ln{(1+0.05)}}
b A LaTex expression showing t = 1 over 4 times \ln{\frac{1905 over 400 }}{\ln{(1-0.05)}}
c A LaTex expression showing t = 1 over 4 times \ln{\frac{1905 over 400 }}{\ln{(1+0.05)}}
6
Rearrange this equation to solve for the time given this model of a growth in credit card debt with monthly interest?
A LaTex expression showing 797 =400 times (1+0.09) to the power of (t times 3)
a A LaTex expression showing t = 1 over 3 times \ln{\frac{797 over 400 }}{\ln{(1+0.09)}}
b A LaTex expression showing t = 1 over 3 times \frac{\ln{797 times 400}}{\ln{(1+0.09)}}
c A LaTex expression showing t = 3 times \ln{\frac{797 over 400 }}{\ln{(1+0.09)}}
d A LaTex expression showing t = 3 times \ln{\frac{797 over 400 }}{\ln{(1-0.09)}}
7
Rearrange this equation to solve for the time given this model of a growth in credit card debt with yearly interest?
A LaTex expression showing 1,802 =700 times (1+0.03) to the power of (t over 4 )
a A LaTex expression showing t = 4 times \ln{\frac{1802 over 700 }}{\ln{(1+0.03)}}
b A LaTex expression showing t = 1 over 4 times \ln{\frac{1802 over 700 }}{\ln{(1+0.03)}}
c A LaTex expression showing t = 4 times \frac{\ln{1802 times 700}}{\ln{(1+0.03)}}
d A LaTex expression showing t = 1 over 4 times \ln{\frac{1802 over 700 }}{\ln{(1-0.03)}}
8
Rearrange this equation to solve for the time given this model of a quarterly compounding growth of money in a savings account?
A LaTex expression showing 1,521 =300 times (1+0.07) to the power of (t over 3 )
a A LaTex expression showing t = 1 over 3 times \ln{\frac{1521 over 300 }}{\ln{(1-0.07)}}
b A LaTex expression showing t = 3 times \frac{\ln{1521 times 300}}{\ln{(1+0.07)}}
c A LaTex expression showing t = 3 times \ln{\frac{1521 over 300 }}{\ln{(1+0.07)}}
d A LaTex expression showing t = 1 over 3 times \ln{\frac{1521 over 300 }}{\ln{(1+0.07)}}