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Exponential Function Solving - Growth (Discrete, Mis-matched Time Units) Equation to Starting Value

Level 1

The topics in this unit focus on mastering exponential growth and decay functions. Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

WorksheetView

Exponential Function Solving - Growth (Discrete, Mis-matched Time Units) Equation to Starting Value Worksheet

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Exponential Function Solving - Growth (Discrete, Mis-matched Time Uni...
1
Solve for the starting cash given this model of a monthly compounding growth of money in a savings account?
A LaTex expression showing 648 =P sub 0 times (1+0.04) to the power of (2 times 3)
a A LaTex expression showing P sub 0 = P over (1+r) to the power of t times 3
b A LaTex expression showing P sub 0 = P times (1+r) to the power of t over 3
c A LaTex expression showing P sub 0 = P over (1-r) to the power of t times 3
2
Solve for the starting debt given this model of a growth in credit card debt with yearly interest?
A LaTex expression showing 12,864 =D sub 0 times (1+0.07) to the power of (48 over 12 )
a A LaTex expression showing D sub 0 = D times (1+r) to the power of t times 12
b A LaTex expression showing D sub 0 = D over (1-r) to the power of \frac{t {12 }}
c A LaTex expression showing D sub 0 = D over (1+r) to the power of \frac{t {12 }}
3
Solve for the starting cash given this model of a monthly compounding growth of money in a savings account?
A LaTex expression showing 771 =P sub 0 times (1+0.05) to the power of (2 times 3)
a A LaTex expression showing P sub 0 = P over (1+r) to the power of t times 3
b A LaTex expression showing P sub 0 = P times (1+r) to the power of t over 3
4
Solve for the starting cash given this model of a monthly compounding growth of money in a savings account?
A LaTex expression showing 225 =P sub 0 times (1+0.03) to the power of (4 times 3)
a A LaTex expression showing P sub 0 = P over (1-r) to the power of t times 3
b A LaTex expression showing P sub 0 = P times (1+r) to the power of t over 3
c A LaTex expression showing P sub 0 = P over (1+r) to the power of t times 3
5
Solve for the starting cash given this model of a quarterly compounding growth of money in a savings account?
A LaTex expression showing 750 =P sub 0 times (1+0.07) to the power of (6 times 4)
a A LaTex expression showing P sub 0 = P over (1+r) to the power of t times 4
b A LaTex expression showing P sub 0 = P times (1+r) to the power of t over 4
c A LaTex expression showing P sub 0 = P over (1-r) to the power of t times 4
6
Solve for the starting cash given this model of a yearly compounding growth of money in a savings account?
A LaTex expression showing 3,193 =P sub 0 times (1+0.08) to the power of (36 over 12 )
a A LaTex expression showing P sub 0 = P times (1+r) to the power of t times 12
b A LaTex expression showing P sub 0 = P over (1-r) to the power of \frac{t {12 }}
c A LaTex expression showing P sub 0 = P over (1+r) to the power of \frac{t {12 }}
7
Solve for the starting debt given this model of a growth in credit card debt with monthly interest?
A LaTex expression showing 930 =D sub 0 times (1+0.05) to the power of (9 times 3)
a A LaTex expression showing D sub 0 = D over (1-r) to the power of t times 3
b A LaTex expression showing D sub 0 = D times (1+r) to the power of t over 3
c A LaTex expression showing D sub 0 = D over (1+r) to the power of t times 3
8
Solve for the starting cash given this model of a quarterly compounding growth of money in a savings account?
A LaTex expression showing 973 =P sub 0 times (1+0.04) to the power of (5 times 4)
a A LaTex expression showing P sub 0 = P times (1+r) to the power of t over 4
b A LaTex expression showing P sub 0 = P over (1-r) to the power of t times 4
c A LaTex expression showing P sub 0 = P over (1+r) to the power of t times 4