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Exponential Function Growth (Discrete) - Scenario to Equation

Level 1

This math topic focuses on constructing and identifying exponential growth equations from given scenarios. The problems involve real-life applications such as calculating the growth of savings in a bank account, the increase of an insect population, and the accrual of debt on a credit card. Each scenario provides specific details like the initial amount, the rate of growth, and the time span, challenging the learner to select the corresponding exponential function equation that accurately represents the situation described.

Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

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Exponential Function Growth (Discrete) - Scenario to Equation Worksheet

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Exponential Function Growth (Discrete) - Scenario to Equation
1
A savings account starts with $800. Each subsequent quarter it earns 9% in interest. After 5 quarters it has $1,230.
Which equation describes this scenario?
a A LaTex expression showing 1,230 =800 times (1+0.09) to the power of (5)
b A LaTex expression showing 1,230 =900 times (1+0.08) to the power of (5)
c A LaTex expression showing 1,230 =500 times (1+0.09) to the power of (8)
2
An insect population starts at 300. Each subsequent yearly breeding season it grows by 2%. After 4 years it has increased to a population of 324.
Which equation describes this scenario?
a A LaTex expression showing 324 =400 times (1+0.02) to the power of (3)
b A LaTex expression showing 324 =300 times (1+0.04) to the power of (2)
c A LaTex expression showing 324 =300 times (1+0.02) to the power of (4)
d A LaTex expression showing 324 =200 times (1+0.03) to the power of (4)
3
A savings account starts with $600. Each subsequent year it earns 2% in interest. After 9 years it has $717.
Which equation describes this scenario?
a A LaTex expression showing 717 =200 times (1+0.06) to the power of (9)
b A LaTex expression showing 717 =600 times (1+0.02) to the power of (9)
c A LaTex expression showing 717 =900 times (1+0.02) to the power of (6)
4
An insect population starts at 300. Each subsequent yearly breeding season it grows by 6%. After 9 years it has increased to a population of 506.
Which equation describes this scenario?
a A LaTex expression showing 506 =300 times (1+0.06) to the power of (9)
b A LaTex expression showing 506 =600 times (1+0.03) to the power of (9)
c A LaTex expression showing 506 =300 times (1+0.09) to the power of (6)
d A LaTex expression showing 506 =900 times (1+0.06) to the power of (3)
5
A credit card starts with $800 of debt. Each subsequent quarter it grows by 2% in interest. After 3 quarters the debt has grown to $848.
Which equation describes this scenario?
a A LaTex expression showing 848 =300 times (1+0.02) to the power of (8)
b A LaTex expression showing 848 =200 times (1+0.08) to the power of (3)
c A LaTex expression showing 848 =800 times (1+0.03) to the power of (2)
d A LaTex expression showing 848 =800 times (1+0.02) to the power of (3)
6
An insect population starts at 500. Each subsequent yearly breeding season it grows by 6%. After 9 years it has increased to a population of 844.
Which equation describes this scenario?
a A LaTex expression showing 844 =500 times (1+0.09) to the power of (6)
b A LaTex expression showing 844 =500 times (1+0.06) to the power of (9)
c A LaTex expression showing 844 =900 times (1+0.06) to the power of (5)
d A LaTex expression showing 844 =600 times (1+0.05) to the power of (9)
7
An insect population starts at 900. Each subsequent yearly breeding season it grows by 6%. After 2 years it has increased to a population of 1,011.
Which equation describes this scenario?
a A LaTex expression showing 1,011 =900 times (1+0.06) to the power of (2)
b A LaTex expression showing 1,011 =600 times (1+0.09) to the power of (2)
c A LaTex expression showing 1,011 =200 times (1+0.06) to the power of (9)
8
A savings account starts with $700. Each subsequent month it earns 4% in interest. After 2 months it has $757.
Which equation describes this scenario?
a A LaTex expression showing 757 =200 times (1+0.04) to the power of (7)
b A LaTex expression showing 757 =700 times (1+0.04) to the power of (2)
c A LaTex expression showing 757 =700 times (1+0.02) to the power of (4)