Exponential Function Solution Equation - Growth (Discrete) Scenario to Time (Level 1)

Exponential Function Solution Equation - Growth (Discrete) Scenario t...

A rabbit population starts at 200. Each subsequent yearly breeding season it grows by 5%. After a certain number of years it has increased to a population of 243 rabbits.

Rearrange the exponential equation to solve for for the time given this scenario?

a $A LaTex expression showing t = \ln{\frac{243 over 200 }}{\ln{(1-0.05)}}$

b $A LaTex expression showing t = \ln{\frac{243 over 200 }}{\ln{(1+0.05)}}$

c $A LaTex expression showing t = \frac{\ln{243 times 200}}{\ln{(1+0.05)}}$

A credit card starts with $500 of debt. Each subsequent quarter it grows by 2% in interest. After a certain number of quarters the debt has grown to $530.

Rearrange the exponential equation to solve for for the time given this scenario?

a $A LaTex expression showing t = \frac{\ln{530 times 500}}{\ln{(1+0.02)}}$

b $A LaTex expression showing t = \ln{\frac{530 over 500 }}{\ln{(1+0.02)}}$

A savings account starts with $700. Each subsequent year it earns 3% in interest. After a certain number of years it has $913.

Rearrange the exponential equation to solve for for the time given this scenario?

a $A LaTex expression showing t = \ln{\frac{913 over 700 }}{\ln{(1-0.03)}}$

b $A LaTex expression showing t = \ln{\frac{913 over 700 }}{\ln{(1+0.03)}}$

c $A LaTex expression showing t = \frac{\ln{913 times 700}}{\ln{(1+0.03)}}$

A savings account starts with $600. Each subsequent year it earns 3% in interest. After a certain number of years it has $636.

Rearrange the exponential equation to solve for for the time given this scenario?

a $A LaTex expression showing t = \ln{\frac{636 over 600 }}{\ln{(1-0.03)}}$

b $A LaTex expression showing t = \ln{\frac{636 over 600 }}{\ln{(1+0.03)}}$

A credit card starts with $300 of debt. Each subsequent quarter it grows by 9% in interest. After a certain number of quarters the debt has grown to $503.

Rearrange the exponential equation to solve for for the time given this scenario?

a $A LaTex expression showing t = \frac{\ln{503 times 300}}{\ln{(1+0.09)}}$

b $A LaTex expression showing t = \ln{\frac{503 over 300 }}{\ln{(1+0.09)}}$

c $A LaTex expression showing t = \ln{\frac{503 over 300 }}{\ln{(1-0.09)}}$

A savings account starts with $700. Each subsequent year it earns 2% in interest. After a certain number of years it has $788.

Rearrange the exponential equation to solve for for the time given this scenario?

a $A LaTex expression showing t = \frac{\ln{788 times 700}}{\ln{(1+0.02)}}$

b $A LaTex expression showing t = \ln{\frac{788 over 700 }}{\ln{(1-0.02)}}$

c $A LaTex expression showing t = \ln{\frac{788 over 700 }}{\ln{(1+0.02)}}$

An insect population starts at 700. Each subsequent yearly breeding season it grows by 8%. After a certain number of years it has increased to a population of 816.

Rearrange the exponential equation to solve for for the time given this scenario?

a $A LaTex expression showing t = \ln{\frac{816 over 700 }}{\ln{(1+0.08)}}$

b $A LaTex expression showing t = \ln{\frac{816 over 700 }}{\ln{(1-0.08)}}$

A rabbit population starts at 700. Each subsequent yearly breeding season it grows by 3%. After a certain number of years it has increased to a population of 811 rabbits.

Rearrange the exponential equation to solve for for the time given this scenario?

a $A LaTex expression showing t = \ln{\frac{811 over 700 }}{\ln{(1+0.03)}}$

b $A LaTex expression showing t = \ln{\frac{811 over 700 }}{\ln{(1-0.03)}}$

c $A LaTex expression showing t = \frac{\ln{811 times 700}}{\ln{(1+0.03)}}$

Exponential Function Solution Equation - Growth (Discrete) Scenario to Time

Exponential Function Solution Equation - Growth (Discrete) Scenario to Time Worksheet