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Exponential Function Solving - Growth (Discrete, Mis-matched Time Units) Scenario to Rate

Level 1

The topics in this unit focus on mastering exponential growth and decay functions. Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

WorksheetView

Exponential Function Solving - Growth (Discrete, Mis-matched Time Units) Scenario to Rate Worksheet

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Exponential Function Solving - Growth (Discrete, Mis-matched Time Uni...
1
A savings account starts with $300. Each subsequent month it earns a certain percent interest. After 5 quarters it has $461.
How would you solve for the rate given this scenario?
a A LaTex expression showing r = +(P over P sub 0 ) to the power of t times 3 over 2 - 1
b A LaTex expression showing r = +(P over P sub 0 ) to the power of 1 over t times 3 - 1
c A LaTex expression showing r = +(P over P sub 0 ) to the power of 1 over \frac{t {3 } } + 1
2
A credit card starts with $800 of debt. Each subsequent month it grows by a certain percent interest. After 2 years the debt has grown to $898.
How would you solve for the rate given this scenario?
a A LaTex expression showing r = +(D over D sub 0 ) to the power of t times 12 over 2 - 1
b A LaTex expression showing r = +(D over D sub 0 ) to the power of 1 over \frac{t {12 } } + 1
c A LaTex expression showing r = +(D over D sub 0 ) to the power of 1 over t times 12 - 1
3
A credit card starts with $900 of debt. Each subsequent quarter it grows by a certain percent interest. After 15 months the debt has grown to $2,483.
How would you solve for the rate given this scenario?
a A LaTex expression showing r = +(D over D sub 0 ) to the power of \frac{t over 3 {2} } - 1
b A LaTex expression showing r = +(D over D sub 0 ) to the power of 1 over \frac{t {3 } } - 1
4
A savings account starts with $800. Each subsequent quarter it earns a certain percent interest. After 9 months it has $956.
How would you solve for the rate given this scenario?
a A LaTex expression showing r = +(P over P sub 0 ) to the power of 1 over \frac{t {3 } } - 1
b A LaTex expression showing r = +(P over P sub 0 ) to the power of \frac{t over 3 {2} } - 1
c A LaTex expression showing r = +(P over P sub 0 ) to the power of 1 over t times 3 + 1
5
A savings account starts with $600. Each subsequent year it earns a certain percent interest. After 36 quarters it has $9,580.
How would you solve for the rate given this scenario?
a A LaTex expression showing r = +(P over P sub 0 ) to the power of \frac{t over 4 {2} } - 1
b A LaTex expression showing r = +(P over P sub 0 ) to the power of 1 over t times 4 + 1
c A LaTex expression showing r = +(P over P sub 0 ) to the power of 1 over \frac{t {4 } } - 1
6
A credit card starts with $700 of debt. Each subsequent year it grows by a certain percent interest. After 8 quarters the debt has grown to $1,034.
How would you solve for the rate given this scenario?
a A LaTex expression showing r = +(D over D sub 0 ) to the power of 1 over \frac{t {4 } } - 1
b A LaTex expression showing r = +(D over D sub 0 ) to the power of \frac{t over 4 {2} } - 1
7
A credit card starts with $300 of debt. Each subsequent month it grows by a certain percent interest. After 2 quarters the debt has grown to $356.
How would you solve for the rate given this scenario?
a A LaTex expression showing r = +(D over D sub 0 ) to the power of t times 3 over 2 - 1
b A LaTex expression showing r = +(D over D sub 0 ) to the power of 1 over t times 3 - 1
c A LaTex expression showing r = +(D over D sub 0 ) to the power of 1 over \frac{t {3 } } + 1
8
A credit card starts with $700 of debt. Each subsequent quarter it grows by a certain percent interest. After 2 years the debt has grown to $742.
How would you solve for the rate given this scenario?
a A LaTex expression showing r = +(D over D sub 0 ) to the power of t times 4 over 2 - 1
b A LaTex expression showing r = +(D over D sub 0 ) to the power of 1 over t times 4 - 1