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Exponential Function Solving - Growth (Discrete, Mis-matched Time Units) Scenario to Starting Value

Level 1

The topics in this unit focus on mastering exponential growth and decay functions. Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

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Exponential Function Solving - Growth (Discrete, Mis-matched Time Units) Scenario to Starting Value Worksheet

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Exponential Function Solving - Growth (Discrete, Mis-matched Time Uni...
1
A savings account starts with a certain amount of cash. Each subsequent quarter it earns 6% in interest. After 9 years it has $1,351.
How would you solve for the starting cash given this scenario?
a A LaTex expression showing P sub 0 = P times (1+r) to the power of t over 4
b A LaTex expression showing P sub 0 = P over (1-r) to the power of t times 4
c A LaTex expression showing P sub 0 = P over (1+r) to the power of t times 4
2
A savings account starts with a certain amount of cash. Each subsequent quarter it earns 8% in interest. After 27 months it has $4,792.
How would you solve for the starting cash given this scenario?
a A LaTex expression showing P sub 0 = P times (1+r) to the power of t times 3
b A LaTex expression showing P sub 0 = P over (1+r) to the power of \frac{t {3 }}
c A LaTex expression showing P sub 0 = P over (1-r) to the power of \frac{t {3 }}
3
A savings account starts with a certain amount of cash. Each subsequent quarter it earns 4% in interest. After 6 months it has $885.
How would you solve for the starting cash given this scenario?
a A LaTex expression showing P sub 0 = P over (1+r) to the power of \frac{t {3 }}
b A LaTex expression showing P sub 0 = P times (1+r) to the power of t times 3
4
A credit card starts with a certain amount of debt. Each subsequent month it grows by 4% in interest. After 9 years the debt has grown to $996.
How would you solve for the starting debt given this scenario?
a A LaTex expression showing D sub 0 = D over (1+r) to the power of t times 12
b A LaTex expression showing D sub 0 = D over (1-r) to the power of t times 12
5
A savings account starts with a certain amount of cash. Each subsequent month it earns 8% in interest. After 2 years it has $1,049.
How would you solve for the starting cash given this scenario?
a A LaTex expression showing P sub 0 = P times (1+r) to the power of t over 12
b A LaTex expression showing P sub 0 = P over (1+r) to the power of t times 12
c A LaTex expression showing P sub 0 = P over (1-r) to the power of t times 12
6
A savings account starts with a certain amount of cash. Each subsequent month it earns 7% in interest. After 6 years it has $1,200.
How would you solve for the starting cash given this scenario?
a A LaTex expression showing P sub 0 = P times (1+r) to the power of t over 12
b A LaTex expression showing P sub 0 = P over (1-r) to the power of t times 12
c A LaTex expression showing P sub 0 = P over (1+r) to the power of t times 12
7
A savings account starts with a certain amount of cash. Each subsequent quarter it earns 3% in interest. After 24 months it has $1,219.
How would you solve for the starting cash given this scenario?
a A LaTex expression showing P sub 0 = P over (1-r) to the power of \frac{t {3 }}
b A LaTex expression showing P sub 0 = P over (1+r) to the power of \frac{t {3 }}
8
A savings account starts with a certain amount of cash. Each subsequent quarter it earns 6% in interest. After 4 years it has $378.
How would you solve for the starting cash given this scenario?
a A LaTex expression showing P sub 0 = P times (1+r) to the power of t over 4
b A LaTex expression showing P sub 0 = P over (1+r) to the power of t times 4