Logarithmic Scales - Magnitude Difference to Measured Value Ratio

Level 1

This math topic focuses on solving problems related to logarithmic scales, specifically the relationship between magnitude differences and measured value ratios across various scientific contexts. It covers: 1. Calculating ratios of hydrogen ion concentrations given differences in pH levels. 2. Determining ratios of seismic wave sizes related to differences in earthquake magnitudes on the Richter scale. 3. Understanding how changes in decibel levels affect the ratios of sound energy. These problems utilize fundamental concepts of logarithmic functions to interpret real-world phenomena such as acidity, earthquake intensity, and sound loudness.

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Logarithmic Scales - Magnitude Difference to Measured Value Ratio Worksheet

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Logarithmic Scales - Magnitude Difference to Measured Value Ratio
1
A LaTex expression showing \text{pH} = -\log{[\text{H} to the power of + ]}\\ \\ \text{pH} sub 2 - \text{pH} sub 1 = -3
If a solution has a pH 3 lower on the pH scale what is the ratio of their Hydrogen ion concentration measurements?
a A LaTex expression showing \frac{[\text{H} to the power of + ] sub 2 }{[\text{H} to the power of + ] sub 1 } = 31,623
b A LaTex expression showing \frac{[\text{H} to the power of + ] sub 2 }{[\text{H} to the power of + ] sub 1 } = 1,000
2
A LaTex expression showing \text{M} = \log{(\frac{\text{I}}{\text{I} sub 0 })}\\ \\ \text{M} sub 2 - \text{M} sub 1 = 3
If an earthquake has a magnitude 3 higher on the Richter scale what is the ratio of their wave size measurements?
a A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 31,623
b A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 1,000
3
A LaTex expression showing \text{dB} = 10\log{(\frac{\text{I}}{\text{I} sub 0 })}\\ \\ \beta sub 2 - \beta sub 1 = 30
If a sound has a dB magnitude 30 higher on the decibel scale what is the ratio of their sound energy measurements?
a A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 1,000
b A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 631
4
A LaTex expression showing \text{dB} = 10\log{(\frac{\text{I}}{\text{I} sub 0 })}\\ \\ \beta sub 2 - \beta sub 1 = 50
If a sound has a dB magnitude 50 higher on the decibel scale what is the ratio of their sound energy measurements?
a A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 100,000
b A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 199,526
5
A LaTex expression showing \text{M} = \log{(\frac{\text{I}}{\text{I} sub 0 })}\\ \\ \text{M} sub 2 - \text{M} sub 1 = 1
If an earthquake has a magnitude 1 higher on the Richter scale what is the ratio of their wave size measurements?
a A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 1
b A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 10
6
A LaTex expression showing \text{dB} = 10\log{(\frac{\text{I}}{\text{I} sub 0 })}\\ \\ \beta sub 2 - \beta sub 1 = 100
If a sound has a dB magnitude 100 higher on the decibel scale what is the ratio of their sound energy measurements?
a A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 3.16 multiplied by 10 to the power of 10
b A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 1 multiplied by 10 to the power of 10
7
A LaTex expression showing \text{dB} = 10\log{(\frac{\text{I}}{\text{I} sub 0 })}\\ \\ \beta sub 2 - \beta sub 1 = 40
If a sound has a dB magnitude 40 higher on the decibel scale what is the ratio of their sound energy measurements?
a A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 3,162
b A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 10,000
8
A LaTex expression showing \text{M} = \log{(\frac{\text{I}}{\text{I} sub 0 })}\\ \\ \text{M} sub 2 - \text{M} sub 1 = 7
If an earthquake has a magnitude 7 higher on the Richter scale what is the ratio of their wave size measurements?
a A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 1 multiplied by 10 to the power of 7
b A LaTex expression showing \frac{\text{I} sub 2 }{\text{I} sub 1 } = 3.16 multiplied by 10 to the power of 7