Trigonometry Identities - Half Angle Identity True/False (Greek Letter)

Level 1

This math topic focuses on verifying half-angle trigonometric identities. It includes problems that present various half-angle identities involving the trigonometric functions sine, cosine, and tangent. For each identity expressed using a Greek letter variable, students are asked to determine whether the identity is correct or incorrect. This practice helps reinforce understanding of trigonometric identities, specifically the half-angle formulas, which are fundamental in trigonometry and useful in solving various problems in mathematics and physics.

Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

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Trigonometry Identities - Half Angle Identity True/False (Greek Letter) Worksheet

Trigonometry Identities - Half Angle Identity True/False (Greek Lette...

$A LaTex expression showing \text{cos}{(\beta over 2 )} = \pmsquare root of \frac{1+\text{sin(\beta)}{2}}$

Is this half-angle identity correct?

Yes

$A LaTex expression showing \text{tan}{(\beta over 2 )} = \pmsquare root of \frac{1-\text{cos(\beta)}{1+\text{cos}(\beta)}}$

Is this half-angle identity correct?

Yes

$A LaTex expression showing \text{tan}{(\gamma over 2 )} = \frac{\text{sin}(\gamma)}{1+\text{cos}(\gamma)}$

Is this half-angle identity correct?

Yes

$A LaTex expression showing \text{sin}{(\beta over 2 )} = \pmsquare root of \frac{1+\text{cos(\beta)}{1-\text{cos}(\beta}}$

Is this half-angle identity correct?

Yes

$A LaTex expression showing \text{sin}{(\alpha over 2 )} = \pmsquare root of \frac{1+\text{cos(\alpha)}{1-\text{cos}(\alpha}}$

Is this half-angle identity correct?

Yes

$A LaTex expression showing \text{tan}{(\beta over 2 )} = \pmsquare root of \frac{1+\text{sin(\beta)}{2}}$

Is this half-angle identity correct?

Yes

$A LaTex expression showing \text{tan}{(\alpha over 2 )} = \frac{1+\text{cos}(\alpha)}{\text{csc}(\alpha)}$

Is this half-angle identity correct?

Yes

$A LaTex expression showing \text{sin}{(\beta over 2 )} = \pmsquare root of \frac{1-\text{cos(\beta)}{2}}$

Is this half-angle identity correct?

Yes