Trigonometry, Unit Circle Pythagorean Identity - Cos/Sin to Identity (Degrees, Typical Notation)

Level 1

This math topic focuses on applying the Pythagorean identity within the context of trigonometry and the unit circle, specifically in degrees using typical notation. The problems involve deducing the relations of sine and cosine functions squared for given angles, demonstrating the use of the identity \(\cos^2\theta + \sin^2\theta = 1\). Each problem presents a specific degree measurement, and the task is to determine which trigonometric squared identity correctly applies to the X or Y dimension of the presented triangle. This set of problems is fundamental for understanding relationships in trigonometry within a unit circle framework.

Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

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Trigonometry, Unit Circle Pythagorean Identity - Cos/Sin to Identity (Degrees, Typical Notation) Worksheet

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Trigonometry, Unit Circle Pythagorean Identity - Cos/Sin to Identity ...
1
An svg image showing a math problem
What does Pythagoras tell us about the X dimension of this triangle?
a A LaTex expression showing \cos to the power of 2 {(330 to the power of circle )} = 1 + \sin to the power of 2 {(330 to the power of circle )}
b A LaTex expression showing \cos to the power of 2 {(330 to the power of circle )} = 1 - \sin to the power of 2 {(330 to the power of circle )}
2
An svg image showing a math problem
What does Pythagoras tell us about the Y dimension of this triangle?
a A LaTex expression showing \sin{(120 to the power of circle )} = square root of 1 - \cos to the power of 2 {(120 to the power of circle ) }
b A LaTex expression showing \sin{(120 to the power of circle )} = square root of \cos to the power of 2 {(120 to the power of circle ) + 1}
3
An svg image showing a math problem
What does Pythagoras tell us about the X dimension of this triangle?
a A LaTex expression showing \cos to the power of 2 {(135 to the power of circle )} = 1 - \sin to the power of 2 {(135 to the power of circle )}
b A LaTex expression showing \cos to the power of 2 {(135 to the power of circle )} = 1 + \sin to the power of 2 {(135 to the power of circle )}
4
An svg image showing a math problem
What does Pythagoras tell us about the X dimension of this triangle?
a A LaTex expression showing \cos{(300 to the power of circle )} = square root of \sin to the power of 2 {(300 to the power of circle ) + 1}
b A LaTex expression showing \cos{(300 to the power of circle )} = square root of 1 - \sin to the power of 2 {(300 to the power of circle ) }
5
An svg image showing a math problem
What does Pythagoras tell us about the X dimension of this triangle?
a A LaTex expression showing \cos to the power of 2 {(60 to the power of circle )} = 1 + \sin to the power of 2 {(60 to the power of circle )}
b A LaTex expression showing \cos to the power of 2 {(60 to the power of circle )} = 1 - \sin to the power of 2 {(60 to the power of circle )}
6
An svg image showing a math problem
What does Pythagoras tell us about the Y dimension of this triangle?
a A LaTex expression showing \sin to the power of 2 {(30 to the power of circle )} = 1 + \cos to the power of 2 {(30 to the power of circle )}
b A LaTex expression showing \sin to the power of 2 {(30 to the power of circle )} = 1 - \cos to the power of 2 {(30 to the power of circle )}
7
An svg image showing a math problem
What does Pythagoras tell us about the Y dimension of this triangle?
a A LaTex expression showing \sin to the power of 2 {(225 to the power of circle )} = 1 + \cos to the power of 2 {(225 to the power of circle )}
b A LaTex expression showing \sin to the power of 2 {(225 to the power of circle )} = 1 - \cos to the power of 2 {(225 to the power of circle )}
8
An svg image showing a math problem
What does Pythagoras tell us about the Y dimension of this triangle?
a A LaTex expression showing \sin{(45 to the power of circle )} = square root of \cos to the power of 2 {(45 to the power of circle ) + 1}
b A LaTex expression showing \sin{(45 to the power of circle )} = square root of 1 - \cos to the power of 2 {(45 to the power of circle ) }