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Exponential Function Solution Equation - Growth (Discrete) Equation to Starting Value

Level 1

The topics in this unit focus on understanding how to work with exponential growth and decay functions. Work on practice problems directly here, or download the printable pdf worksheet to practice offline.

WorksheetView

Exponential Function Solution Equation - Growth (Discrete) Equation to Starting Value Worksheet

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Exponential Function Solution Equation - Growth (Discrete) Equation t...
1
Rearrange this equation to solve for the starting debt given this model of a growth in credit card debt with quarterly interest?
A LaTex expression showing 900 =D sub 0 times (1+0.03) to the power of (4)
a A LaTex expression showing D sub 0 = 900 over (1-0.03) to the power of 4
b A LaTex expression showing D sub 0 = 900 over (1+0.03) to the power of 4
2
Rearrange this equation to solve for the starting population given this model of a growth of an insect population that breeds once per year?
A LaTex expression showing 251 =P sub 0 times (1+0.08) to the power of (3)
a A LaTex expression showing P sub 0 = 251 over (1+0.08) to the power of 3
b A LaTex expression showing P sub 0 = 251 over (1-0.08) to the power of 3
3
Rearrange this equation to solve for the starting debt given this model of a growth in credit card debt with yearly interest?
A LaTex expression showing 684 =D sub 0 times (1+0.04) to the power of (8)
a A LaTex expression showing D sub 0 = 684 over (1-0.04) to the power of 8
b A LaTex expression showing D sub 0 = 684 times (1+0.04) to the power of 8
c A LaTex expression showing D sub 0 = 684 over (1+0.04) to the power of 8
4
Rearrange this equation to solve for the starting population given this model of a growth of an insect population that breeds once per year?
A LaTex expression showing 1,125 =P sub 0 times (1+0.05) to the power of (7)
a A LaTex expression showing P sub 0 = 1125 over (1-0.05) to the power of 7
b A LaTex expression showing P sub 0 = 1125 times (1+0.05) to the power of 7
c A LaTex expression showing P sub 0 = 1125 over (1+0.05) to the power of 7
5
Rearrange this equation to solve for the starting population given this model of a growth of a rabbit population (yearly breeding cycle)?
A LaTex expression showing 1,138 =P sub 0 times (1+0.04) to the power of (6)
a A LaTex expression showing P sub 0 = 1138 over (1-0.04) to the power of 6
b A LaTex expression showing P sub 0 = 1138 times (1+0.04) to the power of 6
c A LaTex expression showing P sub 0 = 1138 over (1+0.04) to the power of 6
6
Rearrange this equation to solve for the starting population given this model of a growth of a rabbit population (yearly breeding cycle)?
A LaTex expression showing 1,129 =P sub 0 times (1+0.09) to the power of (4)
a A LaTex expression showing P sub 0 = 1129 over (1+0.09) to the power of 4
b A LaTex expression showing P sub 0 = 1129 times (1+0.09) to the power of 4
7
Rearrange this equation to solve for the starting cash given this model of a monthly compounding growth of money in a savings account?
A LaTex expression showing 1,434 =P sub 0 times (1+0.06) to the power of (8)
a A LaTex expression showing P sub 0 = 1434 times (1+0.06) to the power of 8
b A LaTex expression showing P sub 0 = 1434 over (1-0.06) to the power of 8
c A LaTex expression showing P sub 0 = 1434 over (1+0.06) to the power of 8
8
Rearrange this equation to solve for the starting population given this model of a growth of a rabbit population (yearly breeding cycle)?
A LaTex expression showing 647 =P sub 0 times (1+0.09) to the power of (3)
a A LaTex expression showing P sub 0 = 647 over (1+0.09) to the power of 3
b A LaTex expression showing P sub 0 = 647 over (1-0.09) to the power of 3
c A LaTex expression showing P sub 0 = 647 times (1+0.09) to the power of 3